Hi ZHQ,

Something that has bothered me about the XP awarded for first time rides ok a course.

I’ve done some maths. I may be wrong and check out my calculation for the new Temples route. You are awarding 750 XP and I get the impression that some shorter courses are over awarded.

Check this out:

Example 1: The Glyph Heights

```
• Distance: 34 km
• Elevation: 618 m
• XP awarded: 510
```

Example 2: Elevation Evaluation

```
• Distance: 27.7 km
• Elevation: 410 m
• XP awarded: 492
```

Step 1: Establish Variables and Formulas

Let’s denote:

```
• D as the distance in kilometres (km)
• E as the elevation in metres (m)
• XP as the experience points awarded
```

We need to derive a formula of the form:

XP = aD + bE + c

where a , b , and c are constants to be determined.

Step 2: Set Up Equations

Using the two provided examples, we can set up a system of linear equations:

```
1. 510 = 34a + 618b + c
2. 492 = 27.7a + 410b + c
```

Step 3: Solve for a , b , and c

To solve this system, we need another equation or make assumptions. Let’s assume c (a fixed base XP for completing any course) might be negligible or zero since it simplifies our calculations.

First, subtract the second equation from the first to eliminate c :

510 - 492 = (34a + 618b) - (27.7a + 410b)

18 = 6.3a + 208b

6.3a + 208b = 18

a = \frac{18 - 208b}{6.3}

This gives us a relation between a and b . We can now test some reasonable values for b and check if they fit the examples:

Step 4: Trial and Error for a and b

Let’s consider different values for b :

```
• Suppose b = 0.05 :
```

a = \frac{18 - 208 \times 0.05}{6.3} = \frac{18 - 10.4}{6.3} = \frac{7.6}{6.3} \approx 1.21

We can verify by plugging a = 1.21 and b = 0.05 back into the original equations:

```
1. 510 = 34 \times 1.21 + 618 \times 0.05 + c
```

510 = 34 \times 1.21 + 30.9 + c

510 = 41.14 + 30.9 + c

c = 510 - 72.04

c = 437.96

2. 492 = 27.7 \times 1.21 + 410 \times 0.05 + c

492 = 33.517 + 20.5 + c

492 = 54.017 + c

c = 492 - 54.017

c = 437.983

These values for c are very close, which implies our assumption a \approx 1.21 , b \approx 0.05 , and c \approx 438 is reasonable.

Step 5: Apply the Formula to the New Course

Using the derived formula:

XP = 1.21D + 0.05E + 438

For a course with 39.1 km and 470 m of elevation:

XP = 1.21 \times 39.1 + 0.05 \times 470 + 438

XP = 47.311 + 23.5 + 438

XP = 508.811

Thus, for a course with 39.1 km and 470 m of elevation, the expected XP awarded would be approximately 509.

So…how do you really calculate the XP for any given route?

Ride on,

Dave.